2x^2-320x+10880=0

Solution for 2x^2-320x+10880=0 equation:

2x^2-320x+10880=0

a = 2; b = -320; c = +10880;
Δ = b2-4ac
Δ = -3202-4·2·10880
Δ = 15360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15360}=\sqrt{1024*15}=\sqrt{1024}*\sqrt{15}=32\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-320)-32\sqrt{15}}{2*2}=\frac{320-32\sqrt{15}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-320)+32\sqrt{15}}{2*2}=\frac{320+32\sqrt{15}}{4}
$